(25x^2-30x+12)/(5x-4)

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Solution for (25x^2-30x+12)/(5x-4) equation: 


D( x )

5*x-4 = 0

5*x-4 = 0

5*x-4 = 0

5*x-4 = 0 // + 4

5*x = 4 // : 5

x = 4/5

x in (-oo:4/5) U (4/5:+oo)

(25*x^2-(30*x)+12)/(5*x-4) = 0

(25*x^2-30*x+12)/(5*x-4) = 0

25*x^2-30*x+12 = 0

25*x^2-30*x+12 = 0

DELTA = (-30)^2-(4*12*25)

DELTA = -300

DELTA < 0

1 = 0

1/(5*x-4) = 0

x belongs to the empty set

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